Forces
free-body diagram
Newton's Second law
Highest point: the mass would accelerate quicker back down from the highest point because of the mass.
f=-kx
f=-30.8(9)
f=-277.2N
F=ma
f=0.5(-1.3)
f=-0.65N
Equilibrium point: the mass would not accelerate at the equilibrium because all the forces are balanced.
f=-kx
f=-30.8(0)
f=0
f=ma
f=0.5(1.4)
f=0.7N
Lowest point: the mass would accelerate back up at the a similar rate as the highest point because of the stored energy in the spring when it dropped to the lowest point.
f=-kx
f=-30.8(-7)
f=215.6
F=ma
f=0.5(-1.6)
f=-0.8
f=-kx
f=-30.8(9)
f=-277.2N
F=ma
f=0.5(-1.3)
f=-0.65N
Equilibrium point: the mass would not accelerate at the equilibrium because all the forces are balanced.
f=-kx
f=-30.8(0)
f=0
f=ma
f=0.5(1.4)
f=0.7N
Lowest point: the mass would accelerate back up at the a similar rate as the highest point because of the stored energy in the spring when it dropped to the lowest point.
f=-kx
f=-30.8(-7)
f=215.6
F=ma
f=0.5(-1.6)
f=-0.8